[Axl] Printing contents of a node?

Steven Starr comtuxaps at gmail.com
Tue Sep 11 09:22:52 CEST 2007

Just to help out others here is the complete code that works.

 #include <axl.h>
 #include <stdio.h>

/*How to compile this code.*/
/* gcc parser.c -o parser -I/usr/include/axl  -laxl -lm */

 int main (int argc, char *argv[])
    axlError **error;

    // top level definitions
    axlDoc *doc = NULL;
    axlNode *node = NULL;
    char *value;

    // initialize axl library
    if (! axl_init ()) {
        printf ("Unable to initialize Axl library\n");
          return -1;

    // get current doc reference
    doc = axl_doc_parse_from_file ("test.xml", error);
    if (doc == NULL) {
        axl_error_free (*error);
        return false;

    node = axl_doc_get_root(doc);
    axl_node_dump(node, &value, NULL);
    printf("%s \n", value);

    // release the document
    axl_doc_free (doc);
    axl_free (value);

    // cleanup axl library
    axl_end ();

    return true;

Here is the xml file "test.xml"

<?xml version="1.0" encoding="ISO-8859-1"?>


Here is what the output looks like.

bash-3.2# ./parser

And A Thank You To Francis For They Help :)
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